Prove that the function $f(x) = e^{x}$ does not have any maxima or minima.

(N/A) Given the function $f(x) = e^{x}$.
First,we find the derivative of the function with respect to $x$:
$f^{\prime}(x) = \frac{d}{dx}(e^{x}) = e^{x}$.
For a function to have local maxima or minima,the first derivative $f^{\prime}(x)$ must be equal to $0$ at some point $c$ in the domain.
Setting $f^{\prime}(x) = 0$,we get:
$e^{x} = 0$.
However,the exponential function $e^{x}$ is strictly positive for all real values of $x$ ($e^{x} > 0$ for all $x \in \mathbb{R}$).
Since $e^{x}$ can never be equal to $0$,there exists no value $c \in \mathbb{R}$ such that $f^{\prime}(c) = 0$.
Therefore,the function $f(x) = e^{x}$ does not have any points of local maxima or local minima.